Q. Given :
import pandas as pd
d = {'one' : pd.series([1., 2., 3.], index = ['a', 'b', 'c']), 'two' : pd.series([1., 2., 3., 4.], index = ['a', 'b', 'c', 'd'])}
df = pd.Dataframe(d)
df1 = pd.Dataframe(d, index = ['d', 'b', 'a'])
df2 = pd. Dataframe(d, index = ('d', 'a'), columns = ['two', 'three'])
print(df)
print(df1)
print(df2)
What will Python show the result as if you execute above code?
Answer =
Output :-
one two
a 1.0 1.0
b 2.0 2.0
c 3.0 3.0
d NaN 4.0
one two
d NaN 4.0
b 2.0 2.0
a 1.0 1.0
two three
d 4.0 NaN
a 1.0 NaN
38. import pandas as pd
ReplyDeleteimport numpy as np
kvs = [‘Jetpur’, ‘Junagadh’, ‘Dhoraji’, ‘Rajkot’]
jtp = pd.dataFrame (pd)
print (kvs.jtp)
#Programe is right or will give error ? if it’ll give error how many errors are there ?
A) No Error, Prog will give output C) 2
C) 1 D) 3
import pandas as pd
Deleteimport numpy as np
kvs = ['Jetpur', 'Junagadh', 'Dhoraji', 'Rajkot’']
jtp = pd.dataFrame (pd) # to create dataframe the syntax is : DataFram() not dataFrame()
# to create dataframe we must pass 'list OR dictionary'
print (kvs.jtp) # variable 'kvs' is a list and 'list' object has no attribute 'jtp'
# program will give error
Post a Comment
You can help us by Clicking on ads. ^_^
Please do not send spam comment : )