def myFunc(list1, var1): 2. list1[0] += 2 3. var1 += 2 4. print(Values/variables within called function :, list1, var1)

Q. Consider following program code, which is similar to the previous program but the function myfunc() has some changes as shown below:

1. def myFunc(list1, var1):

2. list1[0] += 2

3. var1 += 2

4. print("Values/variables within called function :", list1, var1)

5. return

6. #__main__

7. list1 = [1]

8. var1 = 1

9. print("Values/variables before function call:", list1, var1)

10. myFunc(list1, var1)

11. print("Values/variables after function call:", list1, var1)

(i) Identify flow of execution in the above program.
(ii) What will be the output of above program?
(iii) What is reason of this output?

Answer :-

(i) 1 -> 7 -> 8 -> 9 -> 10 -> 1 ->2 ->3 -> 4 -> 5 -> 10 -> 11

(ii) Output :-

Values/variables before function call: [1] 1
Values/variables within called function : [3] 3
Values/variables after function call: [3] 1
>>>

(iii) list1 = [1]

var1 = 1 

These are global variable in global environments.

So, 1st output is [1] 1

But If variable and list pass in function then they will in local scope.

So, 2nd Output is [3] 3

After that var1 value again become 1 because variable is in global environments. But list1 value is same because list have no effect of changing environments.